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-.04x^2+8.3x+4.3=0
We add all the numbers together, and all the variables
-0.04x^2+8.3x+4.3=0
a = -0.04; b = 8.3; c = +4.3;
Δ = b2-4ac
Δ = 8.32-4·(-0.04)·4.3
Δ = 69.578
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8.3)-\sqrt{69.578}}{2*-0.04}=\frac{-8.3-\sqrt{69.578}}{-0.08} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8.3)+\sqrt{69.578}}{2*-0.04}=\frac{-8.3+\sqrt{69.578}}{-0.08} $
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